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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4.  
  5. 	int a,b,c,count=0;
  6.  
  7. 	scanf("%d %d %d",&a,&b,&c);
  8.  
  9. 	if(a<b){
  10. 	while(a>b){
  11.  
  12. 	if(c%a==0)
  13. 	count++;	
  14. 	}a++;
  15. 	}
  16.  
  17. 	if(a>b){
  18. 	while(a<b){
  19.  
  20. 	if(c%b==0)
  21. 	count++;
  22. 	}b++;
  23. 	}
  24.  
  25. 	printf("%dから%dの範囲に%dの約数は%d個ある",a,b,c,count);
  26. 	return 0;
  27. }
  28.  
Success #stdin #stdout 0s 5320KB
comments (?)
stdin
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10 1 12
stdout
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10から2の範囲に12の約数は0個ある
https://ideone.com/vqO5Br
language:
C (gcc 8.3)
created:
1 day ago
visibility:
public

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