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  1. #include <stdio.h>
  2. main( ) {
  3. 	int field[4][4] = { {0,1,0,1}, {0,0,0,1}, {1,1,1,0}, {0,1,1,1} };
  4. 	int mines[4][4] = { {0,0,0,0}, {0,0,0,0}, {0,0,0,0}, {0,0,0,0} };
  5. 	int w = 4, h = 4;
  6. 	for (int y = 0; y < h; y++) {
  7. 		for (int x = 0; x < w; x++) {
  8. 			if (field[y][x] == 0) continue;
  9. 			for (int j = y - 1; j <= y + 1; j++) {
  10. 				for (int i = x - 1; i <= x + 1; i++) {
  11. 					if (chkover(w, h, j, i) == 1)
  12. 						mines[j][i] += 1;
  13. 				}
  14. 			}
  15. 		}
  16. 	}
  17. }
  18. int chkover(int w, int h, int j, int i) {
  19. 	if (i >= 0 && i < w && j >= 0 && j < h) return 1;
  20. 	return 0;
  21. }
Success #stdin #stdout 0.01s 5292KB
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https://ideone.com/tZBLSn
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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