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  1. #include <stdio.h>
  2.  
  3. int main() 
  4. {
  5.     int array[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
  6.     int size = sizeof(array) / sizeof(array[0]); 
  7.     printf("Элементы массива в обратном порядке: ");
  8.     for (int i = size - 1; i >= 0; i--) 
  9.     { 
  10.         printf("%d ", array[i]); 
  11.     }
  12.     printf("\n");
  13.     return 0;
  14. }
Success #stdin #stdout 0.01s 5280KB
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Standard input is empty
stdout
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Элементы массива в обратном порядке: 10 9 8 7 6 5 4 3 2 1
https://ideone.com/tLy4et
language:
C (gcc 8.3)
created:
4 days ago
visibility:
public

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