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  1. nums = [5, 12, 7, 9, 21, 7, 14]
  2. aa = nums.count(7)
  3. print("数字出现次数：",aa)
  4. if 99 not in nums:
  5. 	nums.append(99)
  6. print("最新列表1：",nums)
  7.  
  8. bb = nums.remove(7)
  9. print("最新列表2",nums)
  10. cc = nums[1:4]
  11. print("第2-4元素：",cc)
  12.  
  13.  
Success #stdin #stdout 0.07s 14112KB
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stdout
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数字出现次数： 2
最新列表1： [5, 12, 7, 9, 21, 7, 14, 99]
最新列表2 [5, 12, 9, 21, 7, 14, 99]
第2-4元素： [12, 9, 21]
https://ideone.com/r76wux
language:
Python 3 (python  3.12)
created:
2 days ago
visibility:
public

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