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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4.  
  5. 	int data[9],a,b,i;
  6.  
  7. 	scanf("%d",&a);
  8. 	printf("必要金額を入力（１～１０００）：%d\n",a);
  9.  
  10. 	for(i = 9;i >= 0;i --){
  11. 		if(a > data[i]){
  12. 			printf("%d\n",i);
  13. 			a -= data[i];
  14. 		}
  15. 	}
  16. 	return 0;
  17. }
  18.  
Success #stdin #stdout 0s 5320KB
comments (?)
stdin
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200
data[0] = 1
data[1] = 2
data[2] = 4
data[3] = 8
data[4] = 16
data[5] = 32
data[6] = 64
data[7] = 128
data[8] = 256
data[9] = 512
stdout
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必要金額を入力（１～１０００）：200
6
5
4
3
2
1
0
https://ideone.com/p9sCuk
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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