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  1. #include <stdio.h>
  2. int kaijo(int n){
  3. 	int x=1,i;
  4. 	for(i=1;i<=n;i++){
  5. 			x=x*i;
  6. 	}
  7. 	return x;
  8. }
  9. int func(int n){
  10. 	if(n==1)
  11. 	return 1;
  12. 	else
  13. 	return kaijo(n)-func(n-1);
  14. }
  15. int main(void) {
  16. 	// your code goes here
  17. 	int n=4;
  18. 	printf("%d",func(n));
  19. 	return 0;
  20. }
  21.  
Success #stdin #stdout 0s 5284KB
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https://ideone.com/mjKVKO
language:
C (gcc 8.3)
created:
8 days ago
visibility:
public

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