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  1. #include <stdio.h>
  2. int main(){
  3. 	int p[10],at[10],bt[10],ct[10],tat[10],wt[10],i,j,temp=0,n;
  4. 	float awt=0,atat=0;
  5. 	printf("enter no of process:\n");
  6. 	scanf("%d",&n);
  7. 	printf("Enter processes:\n");
  8. 	for(i=0;i<n;i++){
  9. 		scanf("%d",&p[i]);
  10. 	}
  11. 	printf("Enter arrival time of each process:\n");
  12. 	for(i=0;i<n;i++){
  13. 		scanf("%d",&at[i]);
  14. 	}
  15. 	printf("Enter burst time for each processes:\n");
  16. 	for(i=0;i<n;i++){
  17. 		scanf("%d",&bt[i]);
  18. 	}
  19. 	for(i=0;i<n;i++){
  20. 		for(j=0;j<n-i-1;j++){
  21. 			if(at[j]>at[j+1]){
  22. 				temp=p[j+1];
  23. 				p[j+1]=p[j];
  24. 				p[j]=temp;
  25. 				temp=at[j+1];
  26. 				at[j+1]=at[j];
  27. 				at[j]=temp;
  28. 				temp=bt[j+1];
  29. 				bt[j+1]=bt[j];
  30. 				bt[j]=temp;
  31. 			}
  32. 		}
  33. 	}
  34. 	ct[0]=at[0]+bt[0];
  35. 	for(i=1;i<n;i++){
  36. 		temp=0;
  37. 		if(ct[i-1]<at[i]){
  38. 			temp=at[i]-ct[i-1];
  39. 		}
  40. 		ct[i]=bt[i]+ct[i-1]+temp;
  41. 	}
  42. 	printf("\n p\t AT\t BT\t CT\t TAT\t WT\t");
  43. 	for(i=0;i<n;i++){
  44. 		tat[i]=ct[i]-at[i];
  45. 		wt[i]=tat[i]-bt[i];
  46. 		atat+=tat[i];
  47. 		awt+=wt[i];
  48. 	}
  49. 	atat=atat/n;
  50. 	awt=awt/n;
  51. 	for(i=0;i<n;i++){
  52. 		printf("\n P%d\t %d\t %d\t %d\t %f\t %f",p[i],at[i],bt[i],ct[i],tat[i],wt[i]);
  53. 	}
  54. 	printf("avg tuen around time=%d",atat);
  55. 	printf("avg waiting time =%d",awt);
  56. }
Success #stdin #stdout 0.01s 5320KB
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stdin
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3
1 2 3
24 3 3
stdout
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enter no of process:
Enter processes:
Enter arrival time of each process:
Enter burst time for each processes:

 p	 AT	 BT	 CT	 TAT	 WT	
 P2	 3	 32767	 32770	 0.000000	 0.000000
 P3	 3	 1311375888	 1311408658	 0.000000	 0.000000
 P1	 24	 1311375872	 -1672182766	 0.000000	 0.000000avg tuen around time=1311408634avg waiting time =0
https://ideone.com/kDIXmM
language:
C (gcc 8.3)
created:
10 days ago
visibility:
public

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