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  1. # include <stdio.h>
  2.  
  3. int isPalindrome(char s[]){
  4. 	int i,count=0;
  5. 	int cnt=0;
  6. 	for(i=0;s[i]!='\0';i++){
  7. 		count++;
  8. 	}
  9. 	for(i=0;i<(count/2);i++){
  10. 		if(s[i]==s[count-1-i]){
  11. 			cnt++;
  12. 		}
  13. 	}
  14. 	if(count/2==cnt){
  15. 		return 1;
  16. 	}
  17. 	else return 0;
  18. 	//関数の中だけを書き換えてください
  19. 	//回文になっているとき１を返す
  20. 	//回文になっていないとき０を返す
  21. }
  22.  
  23. //メイン関数は書き換えなくてよいです
  24. int main(){
  25.     char s[100];
  26.     scanf("%s",s);
  27.     printf("%s -> %d\n",s,isPalindrome(s));
  28.     return 0;
  29. }
  30.  
Success #stdin #stdout 0s 5292KB
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https://ideone.com/jYnbfv
language:
C (gcc 8.3)
created:
10 days ago
visibility:
public

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