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  1. #include<cstdio>
  2. #include<cstring>
  3. #include<string>
  4.  
  5. int Ile(int & a, int & b, int l, std::string sb[], char * tab)
  6. {
  7. 	if (strlen(tab) < 4)
  8. 	{
  9. 		sb[0] = tab;
  10. 		return 1;
  11. 	}
  12.  
  13. 	if (l % 3 == 0)
  14. 	{
  15. 		a = l / 3;
  16. 		b = 0;
  17. 	}
  18. 	else if (l % 3 == 1)
  19. 	{
  20. 		a = (l / 3) - 1;
  21. 		b = 2;
  22. 	}
  23. 	else
  24. 	{
  25. 		a = l / 3;
  26. 		b = 1;
  27. 	}
  28.  
  29. 	int h = 0, k = 0;
  30.  
  31. 	for (int i = 0; i < a; i++)
  32. 	{
  33. 		for (int j = 0; j < 3; j++)
  34. 			sb[h] += tab[k++];
  35. 		h++;
  36. 	}
  37.  
  38. 	for (int i = 0; i < b; i++)
  39. 	{
  40. 		for (int j = 0; j < 2; j++)
  41. 			sb[h] += tab[k++];
  42.  
  43. 		h++;
  44. 	}
  45.  
  46. 	return h;
  47.  
  48. }
  49.  
  50. int main()
  51. {
  52. 	int n; scanf("%d", &n);
  53. 	char tab[1001];
  54. 	int k = 0;
  55. 	while (scanf("%s", tab) > 0)
  56. 	{
  57. 		std::string sb[1000] = {""};
  58. 		int l = strlen(tab);
  59.  
  60. 		int ile3, ile2;
  61. 		int h = Ile(ile3, ile2, l, sb, tab);
  62. 		//printf("%d\n", h);
  63. 		for (int i = 0; i < h; i++)
  64. 		{
  65. 			if (i == 0 && k > 0)
  66. 			{
  67. 				printf(" ");
  68. 				k++;
  69. 			}
  70.  
  71. 			k += sb[i].length();
  72. 			//printf("%d\n", k);
  73.  
  74. 			if (k >= n)
  75. 			{
  76. 				if (i == 0)
  77. 				{
  78. 					printf("\n%s", sb[i].c_str());
  79. 					k = sb[i].length();
  80. 				}
  81. 				else if (k == n && i == h - 1)
  82. 				{
  83. 					printf("%s\n", sb[i].c_str());
  84. 					k = 0;
  85. 				}
  86. 				else
  87. 				{
  88. 					printf("-\n%s", sb[i].c_str());
  89. 					k = sb[i].length();
  90. 				}
  91. 			}
  92. 			else
  93. 			{
  94. 				printf("%s", sb[i].c_str());
  95. 			}
  96. 		}
  97.  
  98. 	}
  99. 	return 0;
  100. }
Success #stdin #stdout 0.01s 5272KB
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https://ideone.com/aTELAr
language:
C++ (gcc 8.3)
created:
7 days ago
visibility:
public

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