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  1. #include <stdio.h>
  2. #define N 2
  3.  
  4. void Gaussian_elimination(double a[N][N+1]){
  5. 	int i,j,k;
  6. 	double p,d;
  7.  
  8. 	for (i = 0; i < N; i++) {
  9.     	p = a[i][i];
  10.     	for (j = 0; j < (N + 1); j++) {
  11.     		a[i][j] = a[i][j] / p;
  12.     	}
  13. 	    for (j = 0; j < N; j++) {
  14.     		  if (i != j) {
  15.         		d = a[j][i];
  16.         		for (k = i; k < (N + 1); k++) {
  17.         			a[j][k] = a[j][k] - d * a[i][k];
  18.         		}
  19.     		}
  20.     	}
  21. 	 }
  22. }
  23.  
  24. int main(void)
  25. {
  26. 	double a[N][N + 1] = {
  27.     	{1.0, 1.0, 8},
  28.     	{230, 310, 2080}
  29. 	};
  30. 	char *b[1]={"リンゴ","モモ"};
  31. 	int i;
  32.  
  33. 	Gaussian_elimination(a); 
  34.  
  35. 	for (i = 0; i < N; i++) {
  36.     	printf("%s = %f\n", b[i], a[i][N]);
  37. 	}
  38. 	return 0;
  39. }
Success #stdin #stdout 0s 5284KB
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Standard input is empty
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リンゴ = 5.000000
リンゴ = 3.000000
https://ideone.com/ZSvo9f
language:
C (gcc 8.3)
created:
12 hours ago
visibility:
public

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