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  1. #include <stdio.h>
  2. int days[2][13]={{0,31,28,31,30,31,30,31,31,30,31,30,31},{0,31,29,31,30,31,30,31,31,30,31,30,31}};
  3.  
  4. int leap(int year){
  5.     if(year%4==0&&year%100!=0)
  6.      return 1;
  7.     else if(year%400==0)
  8.      return 1;
  9.     else
  10.      return 0;
  11. }
  12.  
  13. int numberofdays(int year, int month, int date){
  14.     int i,sum=0;
  15.     if(leap(1)){
  16.      for(i=1;i<=month;i++)
  17.       sum=sum+days[1][i];
  18.      sum=sum+date;
  19.     }
  20.     else{
  21.      for(i=1;i<=month;i++)
  22.       sum=sum+days[0][i];
  23.      sum=sum+date;
  24.      }
  25.     return sum;
  26. }
  27.  
  28. int main(void) {
  29.     int year,month,date,sum;
  30.     scanf("%d/%d/%d",&year,&month,&date);
  31.     printf("%d日経過",numberofdays(year,month,date));
  32. 	return 0;
  33. }
  34.  
Success #stdin #stdout 0.01s 5320KB
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2006/9/8
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281日経過
https://ideone.com/YijtXL
9-2
language:
C (gcc 8.3)
created:
9 days ago
visibility:
public

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