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  1. #include <stdio.h>
  2. #include <math.h>
  3.  
  4. #define M_PI 3.141592653589
  5.  
  6. int main(void) {
  7.     double E = 5.0,R = 30.0,C = 0.7e-6,t, I;
  8.  
  9.     printf("t (s)\t\tI (A)\n");
  10.  
  11.     for (t = 0.0; t <= 0.002; t += 0.0001) {
  12.         I = (E / R) * (1 - exp(-t / (R * C))); 
  13.         printf("%.5f\t%.5f\n", t, I); 
  14.     }
  15.  
  16.     return 0;
  17. }
Success #stdin #stdout 0s 5288KB
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stdin
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Standard input is empty
stdout
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t (s)		I (A)
0.00000	0.00000
0.00010	0.16524
0.00020	0.16665
0.00030	0.16667
0.00040	0.16667
0.00050	0.16667
0.00060	0.16667
0.00070	0.16667
0.00080	0.16667
0.00090	0.16667
0.00100	0.16667
0.00110	0.16667
0.00120	0.16667
0.00130	0.16667
0.00140	0.16667
0.00150	0.16667
0.00160	0.16667
0.00170	0.16667
0.00180	0.16667
0.00190	0.16667
https://ideone.com/OcwM9u
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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