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  1. #include <stdio.h>
  2. int sum[3];
  3. void calculate(int (*a)[4]) {
  4.     for (int i = 0; i < 3; i++) {
  5. 		sum[i]=0;
  6.         for (int j = 0; j < 4; j++) {
  7.             sum[i] += a[i][j];
  8. 			}
  9. 	}
  10. 	for(int i=0; i<3; i++)
  11. 	printf("sum[%d]=%d ", i , sum[i]);
  12. }
  13.  
  14. int main(void) {
  15.     int a[3][4] = { {1, 2, 3, 4}, {5, 6, 7, 8}, {9, 10, 11, 12} };
  16. 	calculate(a);
  17.  
  18.     return 0;
  19. }
Success #stdin #stdout 0.01s 5292KB
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stdin
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Standard input is empty
stdout
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sum[0]=10 sum[1]=26 sum[2]=42
https://ideone.com/NdMZnA
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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