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  1. #include <stdio.h>
  2.  
  3.  
  4. int Leap(int year) {
  5.     if (year % 400 == 0) return 1;
  6.     else if (year % 100 == 0) return 0;
  7.     else if (year % 4 == 0) return 1;
  8.     else return 0;
  9. }
  10.  
  11.  
  12. int DayMonth(int year, int month) {
  13.     if (month == 4 || month == 6 || month == 9 || month == 11) {
  14.         return 30;
  15.     } else if (month == 2) {
  16.         if (Leap(year)) {
  17.             return 29;
  18.         } else {
  19.             return 28;
  20.         }
  21.     } else {
  22.         return 31;
  23.     }
  24. }
  25.  
  26. int main() {
  27.     int year, month;
  28.  
  29.  
  30.     printf("西暦年と月を入力してください（例: 2024 2）: ");
  31.     scanf("%d %d", &year, &month);
  32.  
  33.  
  34.     if (month < 1 || month > 12) {
  35.         printf("エラー: 月は1〜12の範囲で入力してください。\n");
  36.         return 1;
  37.     }
  38.  
  39.  
  40.     int days = DayMonth(year, month);
  41.     printf("%d年%d月の日数は %d 日です。\n", year, month, days);
  42.  
  43.     return 0;
  44. }
Success #stdin #stdout 0.01s 5320KB
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2025 6
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西暦年と月を入力してください（例: 2024 2）: 2025年6月の日数は 30 日です。
https://ideone.com/MSWW0P
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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