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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. int main() {
  5. 	// your code goes here
  6. 	int d,m,n,a,g,b,a1,i,c;
  7. 	cin>>m;
  8. 	for(i=1;i<=m;i++){  //判断每一个数是否为米合数；
  9. 		cin>>n;
  10. 		d=0;
  11. 		g=n;
  12. 		a=0;
  13. 		while(g>0){  //判断每一个数的位数；
  14. 			g=g/10;
  15. 			a++;
  16. 		}
  17.  
  18. 		g=n;
  19.  
  20. 		while(g>0){    //求某一个数的各个数位乘方之和；
  21. 			a1=a;
  22. 			b=1;
  23. 			while(a1>0){
  24. 				c=g%10;
  25. 				b=b*c;
  26. 				a1--;
  27. 			}
  28. 			g=g/10;
  29. 			d=d+b;
  30. 		}
  31. 		cout<<"d="<<d<<"b="<<b;
  32.  
  33. 		if(d==n) cout<<"T\n";
  34. 		else cout<<"F\n";
  35. 	}
  36. 	return 0;
  37. }
Success #stdin #stdout 0.01s 5284KB
comments (?)
stdin
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3
153
111
152
stdout
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d=153b=1T
d=3b=1F
d=134b=1F
https://ideone.com/LBTwYD
language:
C++ (gcc 8.3)
created:
4 hours ago
visibility:
public

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