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  1. /// Author : Nguyễn Thái Sơn - K18 - KHMT - UIT
  2. /// Training ICPC 2023
  3.  
  4. #include<bits/stdc++.h>
  5. //#include <ext/pb_ds/assoc_container.hpp>
  6. //#include <ext/pb_ds/trie_policy.hpp>
  7. //#include <ext/rope>
  8.  
  9. //#pragma GCC optimize("Ofast")
  10. //#pragma GCC optimization("unroll-loops, no-stack-protector")
  11. //#pragma GCC target("avx,avx2,fma")
  12.  
  13. //using namespace std;
  14. //using namespace __gnu_pbds;
  15. //using namespace __gnu_cxx;
  16.  
  17. #define fi first
  18. #define se second
  19. #define TASK "test"
  20. #define pb push_back
  21. #define EL cout << endl
  22. #define Ti20_ntson int main()
  23. #define in(x) cout << x << endl
  24. #define all(x) (x).begin(),(x).end()
  25. #define getbit(x, i) (((x) >> (i)) & 1)
  26. #define cntbit(x) __builtin_popcount(x)
  27. #define FOR(i,l,r) for (int i = l; i <= r; i++)
  28. #define FORD(i,l,r) for (int i = l; i >= r; i--)
  29. #define Debug(a,n) for (int i = 1; i <= n; i++) cout << a[i] << " "; cout << endl
  30.  
  31. using namespace std;
  32.  
  33. typedef long long ll;
  34. typedef vector<int> vi;
  35. typedef pair<int,int> vii;
  36. typedef unsigned long long ull;
  37. typedef vector<vector<int>> vvi;
  38. int fastMax(int x, int y) { return (((y-x)>>(32-1))&(x^y))^y; }
  39.  
  40. const int N = 5005;
  41. const int oo = INT_MAX;
  42. const int mod = 1e9 + 7;
  43. const int d4x[4] = {-1, 0, 1, 0} , d4y[4] = {0, 1, 0, -1};
  44. const int d8x[8] = {-1, -1, 0, 1, 1, 1, 0, -1}, d8y[8] = {0, 1, 1, 1, 0, -1, -1, -1};
  45.  
  46. int n, dp[N][2], cnt[N], Val[N][N], a[N];
  47. vector<int> Store[N];
  48.  
  49. inline void Read_Input() {
  50. cin >> n;
  51. FOR(i, 1, n) {
  52. int u; cin >> u;
  53. a[i] = u;
  54. if (Store[u].size() == 0) Store[u].push_back(0);
  55. Store[u].push_back(i);
  56. }
  57. }
  58.  
  59. inline void Solve() {
  60. FOR(i, 1, n) {
  61. set<int, greater<int>> S; S.clear();
  62. for (int j = i; j <= n; j++) {
  63. S.erase(cnt[a[j]]);
  64. ++cnt[a[j]];
  65. S.insert(cnt[a[j]]);
  66. int u = *S.begin();
  67. Val[i][j] = max(0, 2 * u - (j - i + 1));
  68. }
  69. for (int j = i; j <= n; j++)
  70. cnt[a[j]]--;
  71. }
  72. int Ans = 0;
  73. FOR(i, 1, n) {
  74. int cnt = Store[i].size();
  75. if (cnt == 0) continue;
  76. Store[i].push_back(n + 1);
  77. FOR(j, 0, cnt)
  78. dp[j][0] = dp[j][1] = -mod;
  79. dp[0][0] = 1;
  80. FOR(l, 0, cnt - 1)
  81. FOR(j, 0, 1) {
  82. FOR(r, l + 1, cnt) {
  83. /// ko lay l + 1
  84. int dis = Store[i][r] - Store[i][l];
  85. if (r != cnt)
  86. dp[r][(j + dis) & 1] = max(dp[r][(j + dis) & 1], dp[l][j] - Val[Store[i][l] + 1][Store[i][r]]);
  87. if ((j + dis) & 1) {
  88. dp[r][0] = max(dp[r][0], dp[l][j] + 1 - Val[Store[i][l] + 1][Store[i][r] - 1]);
  89. }
  90. }
  91. }
  92. Ans = max(Ans, dp[cnt][0]);
  93. }
  94. cout << max(Ans - 2, 0) << '\n';
  95. FOR(i, 1, n)
  96. Store[i].clear();
  97. }
  98.  
  99. Ti20_ntson {
  100. // freopen(TASK".INP","r",stdin);
  101. // freopen(TASK".OUT","w",stdout);
  102. ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
  103. int T = 1;
  104. cin >> T;
  105. while (T -- ) {
  106. Read_Input();
  107. Solve();
  108. }
  109. }
  110.  
  111.  
  112.  
Success #stdin #stdout 0.01s 5284KB
stdin
Standard input is empty
stdout
0