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  1. #include <stdio.h>
  2. int kaijoh(int x){
  3. 	int r;
  4. 	if(x==1){
  5. 		return 1;
  6. 	}
  7. 	else{
  8. 		r=x*kaijoh(x-1);
  9. 		return r;
  10. 	}
  11. }
  12. int main(void) {
  13. 	int i;
  14. 	for(i=1;i<11;i++){
  15. 		printf("%d\n",kaijoh(i));
  16. 	}
  17. 	return 0;
  18. }
  19.  
Success #stdin #stdout 0s 5288KB
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,i
stdout
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126241207205040403203628803628800
https://ideone.com/IYP9MX
2Q-2 1-0
language:
C99 (gcc 8.3)
created:
9 days ago
visibility:
public

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