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  1. def performOps(A):
  2.     m = len(A)
  3.     n = len(A[0])
  4.     B = []
  5.     for i in xrange(len(A)):
  6.         B.append([0] * n)
  7.         for j in xrange(len(A[i])):
  8.             B[i][n - 1 - j] = A[i][j]
  9.     return B
  10.  
  11. A = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12]]
  12. B = performOps(A)
  13. for i in xrange(len(B)):
  14.     for j in xrange(len(B[i])):
  15.         print B[i][j],
Success #stdin #stdout 0.04s 63596KB
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4 3 2 1 8 7 6 5 12 11 10 9
https://ideone.com/478JqD
language:
Python (PyPy 2.7.13)
created:
3 days ago
visibility:
public

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