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  1. #include <stdio.h>
  2.  
  3. void calculate(int (*a)[4]) {
  4.     int sum[3],i, j;
  5.  
  6.     for (i = 0; i < 3; i++) {  
  7.         sum[i] = 0;
  8.         for (j = 0; j < 4; j++) { 
  9.             sum[i] += a[i][j];
  10.         } }
  11.  
  12.     for (i = 0; i < 3; i++) {
  13.         printf("sum[%d] = %d\n", i, sum[i]);
  14.     }
  15. }
  16.  
  17. int main(void) {
  18.     int a[3][4] = {
  19.         {1, 2, 3, 4}, {5, 6, 7, 8},{9, 10, 11, 12}
  20.     };
  21.  
  22.     calculate(a);
  23.  
  24.     return 0;
  25. }
  26.  
Success #stdin #stdout 0.01s 5320KB
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stdin
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Standard input is empty
stdout
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sum[0] = 10
sum[1] = 26
sum[2] = 42
https://ideone.com/0NSYx8
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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